-2[5-(2z+1)]-4=2(3-z)

Solution for -2[5-(2z+1)]-4=2(3-z) equation:

Simplifying
-2[5 + -1(2z + 1)] + -4 = 2(3 + -1z)

Reorder the terms:
-2[5 + -1(1 + 2z)] + -4 = 2(3 + -1z)
-2[5 + (1 * -1 + 2z * -1)] + -4 = 2(3 + -1z)
-2[5 + (-1 + -2z)] + -4 = 2(3 + -1z)

Combine like terms: 5 + -1 = 4
-2[4 + -2z] + -4 = 2(3 + -1z)
[4 * -2 + -2z * -2] + -4 = 2(3 + -1z)
[-8 + 4z] + -4 = 2(3 + -1z)

Reorder the terms:
-8 + -4 + 4z = 2(3 + -1z)

Combine like terms: -8 + -4 = -12
-12 + 4z = 2(3 + -1z)
-12 + 4z = (3 * 2 + -1z * 2)
-12 + 4z = (6 + -2z)

Solving
-12 + 4z = 6 + -2z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '2z' to each side of the equation.
-12 + 4z + 2z = 6 + -2z + 2z

Combine like terms: 4z + 2z = 6z
-12 + 6z = 6 + -2z + 2z

Combine like terms: -2z + 2z = 0
-12 + 6z = 6 + 0
-12 + 6z = 6

Add '12' to each side of the equation.
-12 + 12 + 6z = 6 + 12

Combine like terms: -12 + 12 = 0
0 + 6z = 6 + 12
6z = 6 + 12

Combine like terms: 6 + 12 = 18
6z = 18

Divide each side by '6'.
z = 3

Simplifying
z = 3